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0=3x^2-21x-52
We move all terms to the left:
0-(3x^2-21x-52)=0
We add all the numbers together, and all the variables
-(3x^2-21x-52)=0
We get rid of parentheses
-3x^2+21x+52=0
a = -3; b = 21; c = +52;
Δ = b2-4ac
Δ = 212-4·(-3)·52
Δ = 1065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{1065}}{2*-3}=\frac{-21-\sqrt{1065}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{1065}}{2*-3}=\frac{-21+\sqrt{1065}}{-6} $
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